H_{2}SO_{4} + Na_{2}SO_{3} is an inorganic reaction that produces three products. Let us explore some more interesting facts about this reaction.

**Oil of vitriol or H _{2}SO_{4} is a mineral acid that is very corrosive in nature. Na_{2}SO_{3} is a white-colored solid which is soluble in water.**

H_{2}SO_{4} + Na_{2}SO_{3 }is a reaction that produces SO_{2} as the major product, water, and Na_{2}SO_{4}.In this article, we will look into the various interesting properties like the product formed, type of reaction, intermolecular forces, etc. about this reaction.

## What is the product of H_{2}SO_{4} and Na_{2}SO_{3}?

**SO _{2}, H_{2}O, and Na_{2}SO_{4}**

**are the products formed in the reaction of H**

_{2}SO_{4}+ Na_{2}SO_{3}respectively.**H _{2}SO_{4} + Na_{2}SO_{3}= SO_{2 }+ H_{2}O + Na_{2}SO_{4}**

## What type of reaction is H_{2}SO_{4} + Na_{2}SO_{3}?

**H _{2}SO_{4} + Na_{2}SO_{3 }shows an acid-base or neutralization reaction. In H_{2}SO_{4} + Na_{2}SO_{3} , H_{2}SO_{4} acts as an acid and Na_{2}SO_{3} acts as a base.**

## How to balance H_{2}SO_{4} + Na_{2}SO_{3}?

**To balance H _{2}SO_{4} + Na_{2}SO_{3} we imply the hit and trial method using the given steps.**

**Firstly, write down the complete reaction**.

**Analyze the number of a particular species on both the reactants and products side.****Then write down the complete balanced reaction ensuring that equal number of species is present on LHS and RHS.****H**_{2}SO_{4}+ Na_{2}SO_{3}= SO_{2 }+ H_{2}O + Na_{2}SO_{4}

Atom |
Reactant side |
Product side |

H | 2 | 2 |

S | 2 | 2 |

O | 7 | 7 |

Na | 2 | 2 |

**Balancing the number of atoms on both the sides of the reaction**

## H_{2}SO_{4} + Na_{2}SO_{3} titration

**The titration between strong acid H _{2}SO_{4} and Na_{2}SO_{3} is not feasible to proceed.**

## H_{2}SO_{4} + Na_{2}SO_{3} net ionic equation

**The net ionic equation of the reaction H _{2}SO_{4} + Na_{2}SO_{3} is as follows-**

**2H ^{+}+ SO_{4}^{2-} + 2Na^{+} + SO_{3}^{2-}= SO_{3}^{2-} + 2H^{+} + 2Na^{+} +SO_{4}^{2-}**

## H_{2}SO_{4} + Na_{2}SO_{3} conjugate pairs

**The conjugate pairs of H _{2}SO_{4} and Na_{2}SO_{3} respectively are SO_{4}^{2-} and H_{2}O**.

## H_{2}SO_{4} + Na_{2}SO_{3} intermolecular forces

**The intermolecular forces acting on H _{2}SO_{4} and Na_{2}SO_{3} in the reaction are as follows: **

**Na**_{2}SO_{3}has ion-dipole force acting between Na^{+}and SO_{4}^{2-}**H**_{2}SO_{4}has three intermolecular forces namely Vander Waal, H bonding, and dipole dipole.

## H_{2}SO_{4} + Na_{2}SO_{3} reaction enthalpy

**The reaction enthalpy of H _{2}SO_{4} + Na_{2}SO_{3} is a spontaneous reaction with ΔG =-105.0kJ/mol.**

## Is H_{2}SO_{4} + Na_{2}SO_{3} a buffer solution

**H _{2}SO_{4} + Na_{2}SO_{3} is not a buffer solution**

**as, in H**

_{2}SO_{4}+ Na_{2}SO_{3}**reaction, H**

_{2}SO_{4}is a strong acid and Na_{2}SO_{3}is salt.## Is H_{2}SO_{4} + Na_{2}SO_{3} a complete reaction

**H _{2}SO_{4} + Na_{2}SO_{3} is a complete reaction as stable products like SO_{2}, H_{2}O, and Na_{2}SO_{4 } are formed.**

## Is H_{2}SO_{4} + Na_{2}SO_{3} an exothermic or endothermic reaction

** The reaction H_{2}SO_{4} + Na_{2}SO_{3} is an exothermic reaction as the enthalpy comes out to be negative**.

## Is H_{2}SO_{4} + Na_{2}SO_{3} a redox reaction

** The reaction H_{2}SO_{4} + Na_{2}SO_{3} is not a redox reaction as there is no change in the oxidation states of each atom as the reaction proceeds**.

## Is H_{2}SO_{4} + Na_{2}SO_{3} a precipitation reaction

**H _{2}SO_{4} + Na_{2}SO_{3 }is not a precipitation reaction. **The salt formed in H

_{2}SO

_{4}+ Na

_{2}SO

_{3 }is highly soluble in water so there is no scope for precipitate formation.

## Is H_{2}SO_{4} + Na_{2}SO_{3} reversible or irreversible reaction

**H _{2}SO_{4} + Na_{2}SO_{3} is an irreversible reaction as stable products are formed.**

## Is H_{2}SO_{4} + Na_{2}SO_{3} displacement reaction

**H _{2}SO_{4} + Na_{2}SO_{3 }is not a displacement reaction as no group or atom displaces another group or atom in the reaction.**

#### Conclusion

H_{2}SO_{4} + Na_{2}SO_{3 }is a thermodynamically stable reaction that proceeds with the release of energy.SO_{2} with its characteristic pungent smell is released on the completion of the reaction as a product. There is no change in the oxidation state of any atom as the reactants H_{2}SO_{4} + Na_{2}SO_{3} convert to the products.

Hello….. I am Shubhi Mishra. I share an eternal love for Chemistry. It is never “too much” to learn and think about Chemistry. My qualifications stand as MSc-Chemistry, BSc-BEd(Physical Sciences).

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