H2SO4 (Sulphuric acid) is the strong acid and Fe2S3(Ferric sulphide) is an unstable artificial material. Let us know some facts about the H2SO4 + Fe2S3
Sulphuric acid is also known as oil of vitriol. It is colorless, odorless viscous liquid. Ferric sulphide composed with the elements Sulphur & Iron, it is also known as Iron(III) sulphide. It is solid, black powder.
In this article we will discuss about the reaction between Sulphuric acid and Ferric sulphide, balancing of equation, titration & ionic equation of the reaction.
What is the product of H2SO4 & Fe2S3
Ferric sulphate and Hydrogen sulphide are formed when Sulphuric acid reacts with Ferric sulphide.
3H2SO4 + Fe2S3 = Fe2(SO4)3 + 3H2S
What type of reaction is H2SO4 + Fe2S3
H2SO4 + Fe2S3 is a displacement reaction.
How to balance H2SO4 + Fe2S3
The reaction is balanced using following steps
H2SO4 + Fe2S3 = Fe2(SO4)3 + H2S
- The number of atoms present on both sides is counted, which should be the same.
Reactant Side | Product Side |
---|---|
2-Hydrogen atom | 2-Hydrogen atom |
4-Oxygen atom | 12-Oxygen atom |
4-Sulphur atom | 4-Sulphur atom |
2-Iron atom | 2-Iron atom |
- The number of Oxygen atoms of both the sides of the reaction balance by adding coefficient 3 to the Sulphuric acid molecule at the reactant side.
- 3H2SO4 + Fe2S3 = Fe2(SO4)3 + H2S
- The number of Hydrogen atoms of both sides of the reaction balance by adding coefficient 3 to the Hydrogen sulphide molecule at product side.
- 3H2SO4 + Fe2S3 = Fe2(SO4)3 + 3H2S
- So the balanced chemical reaction is
- 3H2SO4 + Fe2S3 = Fe2(SO4)3 + 3H2S
H2SO4 + Fe2S3 Titration
H2SO4 + Fe2S3 do not undergo titration because there is no equivalence point.
H2SO4 + Fe2S3 net ionic equation
The net ionic equation
3H2+(aq) + Fe2S3 (s) = 2Fe3+ (aq) + 3H2S (g)
The net ionic equation is derived using the steps mentioned below.
- The balanced equation with phases for H2SO4 + Fe2S3
- 3H2SO4 (aq) + Fe2S3 (s) = Fe2(SO4)3 (aq) + 3H2S (g)
- Then the equation written in splitting of compounds
- 3H2+(aq) + 3SO42- (aq) + Fe2S3 (s) = 2Fe3+ (aq) + 3SO42- (aq) + 3H2S (g)
- The net ionic equation is as follows by removing the spectator ions (ions those are same on reactant & product sides)
- 3H2+(aq) + Fe2S3 (s) = 2Fe3+ (aq) + 3H2S (g)
H2SO4 + Fe2S3 conjugate pairs
- The conjugate base of H2SO4 is SO42-
- The conjugate base of Fe2S3 is S32-
H2SO4 & Fe2S3 Intermolecular forces
- Hydogen bonding, dipole-dipole interaction and Van der Waals dispersion are the intermolecular forces in H2SO4
- Ferric sulphide is covalently bonded to each other
H2SO4 + Fe2S3 reaction enthalpy
The reaction enthalpy of H2SO4 + Fe2S3 is -103.33 KJ/mol.
Compound | Moles | Enthalpy of formation, ΔH0f (KJ/mol) |
---|---|---|
H2SO4 | 3 | -814 |
Fe2S3 | 1 | -101.67 |
Fe2(SO4)3 | 1 | -2585.2 |
H2S | 3 | -20.6 |
- The standard enthalpy of a reaction is calculated using the following formula-
- ΔH0f (reaction) = ΣΔH0f (product) – ΣΔH0f (reactants)
- Thus, Enthalpy change = -103.33 KJ/mol
Is H2SO4 + Fe2S3 a buffer solution
H2SO4 + Fe2S3 reaction will not form a buffer solution because Sulphuric acid is a strong acid and there can only be present a weak acid or base in buffer solution.
Is H2SO4 + Fe2S3 a complete reaction
H2SO4 + Fe2S3 is a complete reaction as products like Ferric sulphate and Hydrogen sulphide are formed.
Is H2SO4 + Fe2S3 an exothermic or endothermic reaction
H2SO4 + Fe2S3 is an exothermic reaction because it releases heat to the surrounding during reaction.
Is H2SO4 + Fe2S3 a redox reaction
H2SO4 + Fe2S3 is not a redox reaction because there is no change in oxidation state of atoms of reactant and product side involved during the reaction.
Is H2SO4 + Fe2S3 a precipitation reaction
H2SO4 + Fe2S3 reaction is not a precipitation reaction because no precipitates are formed during the reaction.
Is H2SO4 + Fe2S3 a reversible or irreversible reaction
H2SO4 + Fe2S3 is an irreversible reaction because the product formed do not react to give back reactants under the same condition.
Is H2SO4 + Fe2S3 a displacement reaction
H2SO4 + Fe2S3 is a double displacement reaction, in which sulphate ion is displaced from H2SO4 molecule and sulphur ion from Fe2S3 molecule to form Ferric sulphate and hydrogen sulphide.
3H2++ 3SO42- + Fe23++ S32- = Fe2 (SO4)3 + 3H2S
Conclusion
Sulphuric acid reacts with Ferric sulphide and gives Ferric sulphate and Hydrogen sulphide. It is a double displacement reaction and no oxidation or reduction occurs during the reaction.
Hello …. I am Dr. Tomleshkumar Deshmukh. I have completed my Ph.D.
from RTMNU. My area of research is Organo-Analytical.